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Let’s check out your problem:
g
(
r
)
=
−
1
−
7
r
g
(
6
)
=
□
\begin{array}{l}g(r)=-1-7 r \\ g(6)=\square\end{array}
g
(
r
)
=
−
1
−
7
r
g
(
6
)
=
□
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Home
Math Problems
Grade 6
Multiply using the distributive property
Full solution
Q.
g
(
r
)
=
−
1
−
7
r
g
(
6
)
=
□
\begin{array}{l}g(r)=-1-7 r \\ g(6)=\square\end{array}
g
(
r
)
=
−
1
−
7
r
g
(
6
)
=
□
Substitute
r
r
r
with
6
6
6
:
To find the value of
g
(
6
)
g(6)
g
(
6
)
, we need to substitute
r
r
r
with
6
6
6
in the function
g
(
r
)
=
−
1
−
7
r
g(r) = -1 - 7r
g
(
r
)
=
−
1
−
7
r
.
\newline
g
(
6
)
=
−
1
−
7
(
6
)
g(6) = -1 - 7(6)
g
(
6
)
=
−
1
−
7
(
6
)
Multiply
7
7
7
by
6
6
6
:
Now, we multiply
7
7
7
by
6
6
6
to get the second term of the expression.
\newline
−
1
−
7
(
6
)
=
−
1
−
42
-1 - 7(6) = -1 - 42
−
1
−
7
(
6
)
=
−
1
−
42
Add the numbers together:
Next, we add the two numbers together to get the final value of
g
(
6
)
g(6)
g
(
6
)
.
\newline
−
1
−
42
=
−
43
-1 - 42 = -43
−
1
−
42
=
−
43
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