{:[{[g(1)=50],[g(n)=8-g(n-1)]:}],[g(2)=◻]:}

Given initial condition and recursive formula: We are given the initial condition and the recursive formula for the sequence: g(1) = 50 g(n) = 8 - g(n - 1) To find g(2), we will use the recursive formula with n = 2.Substituting n = 2 into the recursive formula: Substitute n = 2 into the recursive formula: g(2) = 8 - g(2 - 1) g(2) = 8 - g(1) Since we know g(1) = 50, we can substitute that value in: g(2) = 8 - 50Substituting g(1) into the equation: Perform the subtraction to find g(2): g(2) = 8 - 50 g(2) = -42Performing the subtraction: We have found the value of g(2): g(2) = -42

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{:[{[g(1)=50],[g(n)=8-g(n-1)]:}],[g(2)=◻]:}

$\begin{array}{l}\left\{\begin{array}{l}g(1)=50 \\ g(n)=8-g(n-1)\end{array}\right. \\ g(2)=\square\end{array}$

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Algebra 1

Evaluate recursive formulas for sequences

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\begin{array}{l}\left\{\begin{array}{l}g(1)=50 \\ g(n)=8-g(n-1)\end{array}\right. \\ g(2)=\square\end{array}

Given initial condition and recursive formula: We are given the initial condition and the recursive formula for the sequence: $\newline$ $g(1) = 50$ $\newline$ $g(n) = 8 - g(n - 1)$ $\newline$ To find $g(2)$ , we will use the recursive formula with $n = 2$ .
Substituting $n = 2$ into the recursive formula: Substitute $n = 2$ into the recursive formula: $\newline$ $g(2) = 8 - g(2 - 1)$ $\newline$ $g(2) = 8 - g(1)$ $\newline$ Since we know $g(1) = 50$ , we can substitute that value in: $\newline$ $g(2) = 8 - 50$
Substituting $g(1)$ into the equation: Perform the subtraction to find $g(2)$ : $g(2) = 8 - 50$ $g(2) = -42$
Performing the subtraction: We have found the value of $g(2)$ : $g(2) = -42$