{:[{[g(1)=-5],[g(2)=3],[g(n)=g(n-2)+g(n-1)]:}],[g(3)=◻]:}

Given Recursive Sequence: We are given a recursive sequence for the function g(n) with the following initial conditions: g(1) = -5 g(2) = 3 The recursive formula for g(n) is: g(n) = g(n-2) + g(n-1) We need to find the value of g(3).Find g(3): To find g(3), we use the recursive formula and the initial conditions: g(3) = g(1) + g(2) We know that g(1) = -5 and g(2) = 3, so we substitute these values into the equation: g(3) = (-5) + 3Calculation and Result: Now we perform the calculation: g(3) = -5 + 3 g(3) = -2 So, the value of g(3) is -2.

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{:[{[g(1)=-5],[g(2)=3],[g(n)=g(n-2)+g(n-1)]:}],[g(3)=◻]:}

$\begin{cases} g(1) = -5 \\ g(2) = 3 \\ g(n) = g(n-2) + g(n-1) \end{cases}$ $\newline$ $g(3)=\square$

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Algebra 2

Domain and range of absolute value functions: equations

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\begin{cases} g(1) = -5 \\ g(2) = 3 \\ g(n) = g(n-2) + g(n-1) \end{cases}

\newline

g(3)=\square

Given Recursive Sequence: We are given a recursive sequence for the function $g(n)$ with the following initial conditions: $\newline$ $g(1) = -5$ $\newline$ $g(2) = 3$ $\newline$ The recursive formula for $g(n)$ is: $\newline$ $g(n) = g(n-2) + g(n-1)$ $\newline$ We need to find the value of $g(3)$ .
Find $g(3)$ : To find $g(3)$ , we use the recursive formula and the initial conditions: $\newline$ $g(3) = g(1) + g(2)$ $\newline$ We know that $g(1) = -5$ and $g(2) = 3$ , so we substitute these values into the equation: $\newline$ $g(3) = (-5) + 3$
Calculation and Result: Now we perform the calculation: $\newline$ $g(3) = -5 + 3$ $\newline$ $g(3) = -2$ $\newline$ So, the value of $g(3)$ is $-2$ .