{[g(1)=2.7],[g(n)=g(n-1)*6.1]:} Find an explicit formula for g(n). g(n)=

Given Information: We are given the initial value of the function g(1) = 2.7 and the recursive formula g(n) = g(n-1) * 6.1. This indicates that the sequence is geometric, where each term is obtained by multiplying the previous term by the common ratio 6.1.Identifying First Term and Common Ratio: To find an explicit formula for g(n), we need to identify the first term (a1) and the common ratio (r) of the geometric sequence. From the given information, we have: a1 = g(1) = 2.7 r = 6.1Explicit Formula for Geometric Sequence: The explicit formula for a geometric sequence is given by: g(n) = a1 * r^(n - 1) Substituting the values of a1 and r, we get: g(n) = 2.7 * 6.1^(n - 1)

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{[g(1)=2.7],[g(n)=g(n-1)*6.1]:}
Find an explicit formula for
g(n).

g(n)=

$\begin{cases} g(1)=2.7, g(n)=g(n-1)\times 6.1 \end{cases}$ Find an explicit formula for $g(n)$ . $g(n)=$

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Math Problems

Algebra 1

Write variable expressions for geometric sequences

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\begin{cases} g(1)=2.7, g(n)=g(n-1)\times 6.1 \end{cases}

Find an explicit formula for

g(n)

g(n)=

Given Information: We are given the initial value of the function $g(1) = 2.7$ and the recursive formula $g(n) = g(n-1) \times 6.1$ . This indicates that the sequence is geometric, where each term is obtained by multiplying the previous term by the common ratio $6.1$ .
Identifying First Term and Common Ratio: To find an explicit formula for g(n), we need to identify the first term ( $a_1$ ) and the common ratio ( $r$ ) of the geometric sequence. From the given information, we have: $\newline$ $a_1 = g(1) = 2.7$ $\newline$ $r = 6.1$
Explicit Formula for Geometric Sequence: The explicit formula for a geometric sequence is given by: $\newline$ g(n) = a_$1$ $\times r^{(n - 1)}$ $\newline$ Substituting the values of a_$1$ and r, we get: $\newline$ g(n) = $2.7 \times 6.1^{(n - 1)}$