{:[f(x)=(1)/(x-1)],[g(x)=5x+8]:} The functions f and g are defined. What is the value of f(g(-1)) ?

Find g(-1): First, we need to find the value of g(-1) by substituting x with -1 in the function g(x). g(x) = 5x + 8 g(-1) = 5(-1) + 8Calculate g(-1): Now, let's perform the calculation for g(-1). g(-1) = 5(-1) + 8 g(-1) = -5 + 8 g(-1) = 3Substitute into f(x): Next, we need to substitute the value of g(-1) into the function f(x) to find f(g(-1)). f(x) = 1/(x - 1) f(g(-1)) = f(3)Calculate f(3): Now, let's perform the calculation for f(3). f(3) = 1/(3 - 1) f(3) = 1/2Final Result: We have found the value of f(g(-1)), which is f(3), and we have calculated it to be 1/2.

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{:[f(x)=(1)/(x-1)],[g(x)=5x+8]:}
The functions
f and
g are defined. What is the value of
f(g(-1)) ?

$\begin{array}{l} f(x)=\frac{1}{x-1} \\ g(x)=5 x+8 \end{array}$ $\newline$ The functions $f$ and $g$ are defined. What is the value of $f(g(-1))$ ?

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Algebra 2

Domain and range of absolute value functions: equations

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\begin{array}{l} f(x)=\frac{1}{x-1} \\ g(x)=5 x+8 \end{array}

\newline

The functions

f

and

g

are defined. What is the value of

f(g(-1))

Find $g(-1)$ : First, we need to find the value of $g(-1)$ by substituting $x$ with $-1$ in the function $g(x)$ .
$g(x) = 5x + 8$
$g(-1) = 5(-1) + 8$
Calculate $g(-1)$ : Now, let's perform the calculation for $g(-1)$ .
$g(-1) = 5(-1) + 8$
$g(-1) = -5 + 8$
$g(-1) = 3$
Substitute into $f(x)$ : Next, we need to substitute the value of $g(-1)$ into the function $f(x)$ to find $f(g(-1))$ . $\newline$ $f(x) = \frac{1}{(x - 1)}$ $\newline$ $f(g(-1)) = f(3)$
Calculate $f(3)$ : Now, let's perform the calculation for $f(3)$ . $\newline$ $f(3) = \frac{1}{(3 - 1)}$ $\newline$ $f(3) = \frac{1}{2}$
Final Result: We have found the value of $f(g(-1))$ , which is $f(3)$ , and we have calculated it to be $\frac{1}{2}$ .