{[f(1)=-7],[f(n)=f(n-1)+3.5]:} f(3)=

Given initial condition and recursive formula: We are given the initial condition and the recursive formula: f(1) = -7 f(n) = f(n-1) + 3.5 To find f(3), we first need to find f(2).Calculating f(2) using the recursive formula: Using the recursive formula, we calculate f(2): f(2) = f(1) + 3.5 f(2) = -7 + 3.5 f(2) = -3.5Calculating f(3) using the value of f(2): Now we use the value of f(2) to find f(3): f(3) = f(2) + 3.5 f(3) = -3.5 + 3.5 f(3) = 0

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$\begin{array}{l}\left\{\begin{array}{l}f(1)=-7 \\ f(n)=f(n-1)+3.5\end{array}\right. \\ f(3)=\square\end{array}$

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Algebra 1

Evaluate recursive formulas for sequences

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\begin{array}{l}\left\{\begin{array}{l}f(1)=-7 \\ f(n)=f(n-1)+3.5\end{array}\right. \\ f(3)=\square\end{array}

Given initial condition and recursive formula: We are given the initial condition and the recursive formula: $\newline$ f( $1$ ) = $-7$ $\newline$ f(n) = f(n $-1$ ) + $3.5$ $\newline$ To find f( $3$ ), we first need to find f( $2$ ).
Calculating $f(2)$ using the recursive formula: Using the recursive formula, we calculate $f(2)$ :
$f(2) = f(1) + 3.5$
$f(2) = -7 + 3.5$
$f(2) = -3.5$
Calculating $f(3)$ using the value of $f(2)$ : Now we use the value of $f(2)$ to find $f(3)$ :
$f(3) = f(2) + 3.5$
$f(3) = -3.5 + 3.5$
$f(3) = 0$