{:[{[f(1)=-6],[f(2)=-4],[f(n)=f(n-2)+f(n-1)]:}],[f(3)=◻]:}

Given Recursive Function: We are given the following recursive function: f(1) = -6 f(2) = -4 f(n) = f(n-2) + f(n-1) We need to find the value of f(3).Finding f(3): According to the recursive formula, f(3) can be found by adding f(1) and f(2). So, f(3) = f(1) + f(2).Substituting Values: Substitute the given values into the equation: f(3) = f(1) + f(2) = (-6) + (-4).Performing Addition: Perform the addition to find f(3): f(3) = -6 + (-4) = -10.

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{:[{[f(1)=-6],[f(2)=-4],[f(n)=f(n-2)+f(n-1)]:}],[f(3)=◻]:}

$\begin{array}{l}\left\{\begin{array}{l}f(1)=-6 \\ f(2)=-4 \\ f(n)=f(n-2)+f(n-1)\end{array}\right. \\ f(3)=\end{array}$

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Algebra 1

Evaluate recursive formulas for sequences

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\begin{array}{l}\left\{\begin{array}{l}f(1)=-6 \\ f(2)=-4 \\ f(n)=f(n-2)+f(n-1)\end{array}\right. \\ f(3)=\end{array}

Given Recursive Function: We are given the following recursive function: $\newline$ $f(1) = -6$ $\newline$ $f(2) = -4$ $\newline$ $f(n) = f(n-2) + f(n-1)$ $\newline$ We need to find the value of $f(3)$ .
Finding $f(3)$ : According to the recursive formula, $f(3)$ can be found by adding $f(1)$ and $f(2)$ . $\newline$ So, $f(3) = f(1) + f(2)$ .
Substituting Values: Substitute the given values into the equation: $\newline$ $f(3) = f(1) + f(2) = (-6) + (-4)$ .
Performing Addition: Perform the addition to find $f(3)$ : $f(3) = -6 + (-4) = -10.$