{[f(1)=3],[f(n)=f(n-1)+5.5]:} f(3)=

Question Prompt: The question prompt is: ＂What is the value of f(3)?＂Given Function and Initial Value: Given the recursive function f(n) = f(n-1) + 5.5, and knowing that f(1) = 3, we need to find the value of f(3).Finding f(2): First, we find the value of f(2) using the recursive formula: f(2) = f(1) + 5.5 f(2) = 3 + 5.5 f(2) = 8.5Finding f(3): Now, we use the value of f(2) to find f(3): f(3) = f(2) + 5.5 f(3) = 8.5 + 5.5 f(3) = 14

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$\begin{array}{l}\left\{\begin{array}{l}f(1)=3 \\ f(n)=f(n-1)+5.5\end{array}\right. \\ f(3)=\square\end{array}$

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Algebra 1

Evaluate recursive formulas for sequences

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\begin{array}{l}\left\{\begin{array}{l}f(1)=3 \\ f(n)=f(n-1)+5.5\end{array}\right. \\ f(3)=\square\end{array}

Question Prompt: The question prompt is: ＂What is the value of $f(3)$ ?＂
Given Function and Initial Value: Given the recursive function $f(n) = f(n-1) + 5.5$ , and knowing that $f(1) = 3$ , we need to find the value of $f(3)$ .
Finding $f(2)$ : First, we find the value of $f(2)$ using the recursive formula: $\newline$ $f(2) = f(1) + 5.5$ $\newline$ $f(2) = 3 + 5.5$ $\newline$ $f(2) = 8.5$
Finding $f(3)$ : Now, we use the value of $f(2)$ to find $f(3)$ : $\newline$ $f(3) = f(2) + 5.5$ $\newline$ $f(3) = 8.5 + 5.5$ $\newline$ $f(3) = 14$