{:[{[f(1)=25],[f(n)=f(n-1)*(-(1)/(5))]:}],[f(3)=◻]:}

Given initial condition and recursive formula: We are given the initial condition and the recursive formula for the function f: f(1) = 25 f(n) = f(n-1) * (-(1)/(5)) To find f(3), we first need to find f(2) using the recursive formula.Finding f(2) using the recursive formula: Using the recursive formula, we calculate f(2): f(2) = f(1) * (-(1)/(5)) f(2) = 25 * (-(1)/(5)) f(2) = -5 We have found the value of f(2) to be -5.Calculating f(2): Now we can use the value of f(2) to find f(3): f(3) = f(2) * (-(1)/(5)) f(3) = -5 * (-(1)/(5)) f(3) = 1 We have found the value of f(3) to be 1.

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{:[{[f(1)=25],[f(n)=f(n-1)*(-(1)/(5))]:}],[f(3)=◻]:}

$\left\{\begin{array}{l}f(1)=25 \\ f(n)=f(n-1) \cdot\left(-\frac{1}{5}\right)\end{array}\right.$ $\newline$ $f(3)=$

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Algebra 1

Evaluate recursive formulas for sequences

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\left\{\begin{array}{l}f(1)=25 \\ f(n)=f(n-1) \cdot\left(-\frac{1}{5}\right)\end{array}\right.

\newline

f(3)=

Given initial condition and recursive formula: We are given the initial condition and the recursive formula for the function $f$ : $f(1) = 25$ $f(n) = f(n-1) \cdot \left(-\frac{1}{5}\right)$ To find $f(3)$ , we first need to find $f(2)$ using the recursive formula.
Finding $f(2)$ using the recursive formula: Using the recursive formula, we calculate $f(2)$ :
$f(2) = f(1) \cdot \left(-\frac{1}{5}\right)$
$f(2) = 25 \cdot \left(-\frac{1}{5}\right)$
$f(2) = -5$
We have found the value of $f(2)$ to be $-5$ .
Calculating $f(2)$ : Now we can use the value of $f(2)$ to find $f(3)$ : $\newline$ $f(3) = f(2) \cdot \left(-\frac{1}{5}\right)$ $\newline$ $f(3) = -5 \cdot \left(-\frac{1}{5}\right)$ $\newline$ $f(3) = 1$ $\newline$ We have found the value of $f(3)$ to be $1$ .