{[f(1)=-16],[f(n)=f(n-1)*(-(1)/(2))]:} f(3)=

Find f(2): To find f(3), we need to apply the recursive formula twice, starting with the given value of f(1). First, let's find f(2) using the recursive formula: f(n) = f(n-1) * (-(1/2)) f(2) = f(1) * (-(1/2)) f(2) = -16 * (-(1/2)) f(2) = 8Find f(3): Now that we have f(2), we can find f(3) using the same recursive formula: f(n) = f(n-1) * (-(1/2)) f(3) = f(2) * (-(1/2)) f(3) = 8 * (-(1/2)) f(3) = -4

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{[f(1)=-16],[f(n)=f(n-1)*(-(1)/(2))]:}

f(3)=

$\left\{\begin{array}{l}f(1)=-16 \\ f(n)=f(n-1) \cdot\left(-\frac{1}{2}\right)\end{array}\right.$ $\newline$ $f(3)=$

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Algebra 1

Evaluate recursive formulas for sequences

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\left\{\begin{array}{l}f(1)=-16 \\ f(n)=f(n-1) \cdot\left(-\frac{1}{2}\right)\end{array}\right.

\newline

f(3)=

Find $f(2)$ : To find $f(3)$ , we need to apply the recursive formula twice, starting with the given value of $f(1)$ . $\newline$ First, let's find $f(2)$ using the recursive formula: $\newline$ $f(n) = f(n-1) \cdot \left(-\left(\frac{1}{2}\right)\right)$ $\newline$ $f(2) = f(1) \cdot \left(-\left(\frac{1}{2}\right)\right)$ $\newline$ $f(2) = -16 \cdot \left(-\left(\frac{1}{2}\right)\right)$ $\newline$ $f(2) = 8$
Find $f(3)$ : Now that we have $f(2)$ , we can find $f(3)$ using the same recursive formula: $\newline$ $f(n) = f(n-1) \cdot \left(-\frac{1}{2}\right)$ $\newline$ $f(3) = f(2) \cdot \left(-\frac{1}{2}\right)$ $\newline$ $f(3) = 8 \cdot \left(-\frac{1}{2}\right)$ $\newline$ $f(3) = -4$