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{
f
(
1
)
=
15
f
(
n
)
=
f
(
n
−
1
)
⋅
n
f
(
2
)
=
□
\begin{array}{l}\left\{\begin{array}{l}f(1)=15 \\ f(n)=f(n-1) \cdot n\end{array}\right. \\ f(2)=\square\end{array}
{
f
(
1
)
=
15
f
(
n
)
=
f
(
n
−
1
)
⋅
n
f
(
2
)
=
□
View step-by-step help
Home
Math Problems
Algebra 1
Evaluate recursive formulas for sequences
Full solution
Q.
{
f
(
1
)
=
15
f
(
n
)
=
f
(
n
−
1
)
⋅
n
f
(
2
)
=
□
\begin{array}{l}\left\{\begin{array}{l}f(1)=15 \\ f(n)=f(n-1) \cdot n\end{array}\right. \\ f(2)=\square\end{array}
{
f
(
1
)
=
15
f
(
n
)
=
f
(
n
−
1
)
⋅
n
f
(
2
)
=
□
Problem Prompt:
The question prompt asks us to find the value of
f
(
2
)
f(2)
f
(
2
)
given the recursive function
f
(
n
)
=
f
(
n
−
1
)
⋅
n
f(n) = f(n-1) \cdot n
f
(
n
)
=
f
(
n
−
1
)
⋅
n
with the initial condition
f
(
1
)
=
15
f(1) = 15
f
(
1
)
=
15
.
Initial Condition:
We know that
f
(
1
)
=
15
f(1) = 15
f
(
1
)
=
15
. To find
f
(
2
)
f(2)
f
(
2
)
, we use the recursive formula
f
(
n
)
=
f
(
n
−
1
)
⋅
n
f(n) = f(n-1) \cdot n
f
(
n
)
=
f
(
n
−
1
)
⋅
n
with
n
=
2
n = 2
n
=
2
.
Recursive Formula:
Substitute
n
=
2
n = 2
n
=
2
into the recursive formula to get
f
(
2
)
=
f
(
2
−
1
)
×
2
f(2) = f(2-1) \times 2
f
(
2
)
=
f
(
2
−
1
)
×
2
.
Substitute
n
=
2
n = 2
n
=
2
:
Calculate
f
(
2
)
f(2)
f
(
2
)
using the known value of
f
(
1
)
f(1)
f
(
1
)
:
f
(
2
)
=
f
(
1
)
×
2
=
15
×
2
f(2) = f(1) \times 2 = 15 \times 2
f
(
2
)
=
f
(
1
)
×
2
=
15
×
2
.
Calculate
f
(
2
)
f(2)
f
(
2
)
:
Perform the multiplication to find
f
(
2
)
f(2)
f
(
2
)
:
f
(
2
)
=
30
f(2) = 30
f
(
2
)
=
30
.
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