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{[f(1)=-1.8],[f(n)=f(n-1)*9]:}
Find an explicit formula for 
f(n).

f(n)=

{f(1)=1.8,f(n)=f(n1)×9\begin{cases} f(1)=-1.8, f(n)=f(n-1)\times 9 \end{cases} Find an explicit formula for f(n)f(n).f(n)=f(n)=

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Q. {f(1)=1.8,f(n)=f(n1)×9\begin{cases} f(1)=-1.8, f(n)=f(n-1)\times 9 \end{cases} Find an explicit formula for f(n)f(n).f(n)=f(n)=
  1. Given sequence and terms: We are given a recursive sequence where the first term f(1)f(1) is 1.8-1.8 and each subsequent term is obtained by multiplying the previous term by 99. To find an explicit formula, we need to express f(n)f(n) in terms of nn without referring to f(n1)f(n-1).
  2. Identifying the pattern: Let's look at the first few terms to identify a pattern:\newlinef(1)=1.8f(1) = -1.8\newlinef(2)=f(1)×9=1.8×9f(2) = f(1) \times 9 = -1.8 \times 9\newlinef(3)=f(2)×9=(1.8×9)×9f(3) = f(2) \times 9 = (-1.8 \times 9) \times 9\newlineWe can see that each term is the first term multiplied by 99 raised to the power of (n1)(n-1).
  3. Geometric sequence formula: The explicit formula for a geometric sequence is given by:\newlinef(n)=ar(n1)f(n) = a \cdot r^{(n - 1)}\newlinewhere aa is the first term and rr is the common ratio. In this case, a=f(1)=1.8a = f(1) = -1.8 and r=9r = 9.
  4. Substituting values into the formula: Substitute the values of aa and rr into the formula to get the explicit formula for f(n)f(n):f(n)=1.8×9(n1)f(n) = -1.8 \times 9^{(n - 1)}This is the explicit formula for the given recursive sequence.

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