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ddx(yx+xy=2)\frac{d}{dx}\left(\frac{y}{x}+xy=-2\right)

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Q. ddx(yx+xy=2)\frac{d}{dx}\left(\frac{y}{x}+xy=-2\right)
  1. Apply Quotient Rule: We are given the equation (yx)+xy=2(\frac{y}{x}) + xy = -2 and we need to find its derivative with respect to xx. To do this, we will apply the rules of differentiation to each term separately.
  2. Apply Product Rule: First, let's differentiate the term (y/x)(y/x). Since yy is a function of xx, we need to apply the quotient rule which is (v(uu(v))/v2(v(u' - u(v')) / v^2, where u=yu = y and v=xv = x. The derivative of yy with respect to xx is dy/dxdy/dx, and the derivative of xx with respect to xx is yy11. So, the derivative of (y/x)(y/x) is yy33.
  3. Differentiate Constant Term: Next, we differentiate the term xyxy. This is a product of two functions, so we use the product rule which is uv+uvu'v + uv', where u=xu = x and v=yv = y. The derivative of xx with respect to xx is 11, and the derivative of yy with respect to xx is dydx\frac{dy}{dx}. So, the derivative of xyxy is uv+uvu'v + uv'11 which simplifies to uv+uvu'v + uv'22.
  4. Combine Derivatives: Now, we differentiate the constant term 2-2. The derivative of any constant with respect to xx is 00.
  5. Simplify Differential Equation: Combining the derivatives from the previous steps, we get the derivative of the entire equation:\newlineddx[yx+xy]=xdydxyx2+y+xdydx=0\frac{d}{dx}\left[\frac{y}{x} + xy\right] = \frac{x\frac{dy}{dx} - y}{x^2} + y + x\frac{dy}{dx} = 0.
  6. Clear Fraction: We now have a differential equation that we can simplify: \newline(xdydxy)/x2+y+xdydx=0(x\frac{dy}{dx} - y) / x^2 + y + x\frac{dy}{dx} = 0.\newlineMultiplying through by x2x^2 to clear the fraction, we get:\newlinexdydxy+x2y+x3dydx=0x\frac{dy}{dx} - y + x^2y + x^3\frac{dy}{dx} = 0.
  7. Combine Like Terms: Combine like terms to simplify the equation further:\newlinexdydx+x3dydx=yx2yx\frac{dy}{dx} + x^3\frac{dy}{dx} = y - x^2y.\newlineFactor out dydx\frac{dy}{dx} on the left side:\newlinedydx(x+x3)=y(1x2)\frac{dy}{dx} (x + x^3) = y(1 - x^2).
  8. Factor Out dy/dx: Now, we can solve for dydx\frac{dy}{dx} by dividing both sides by (x+x3)(x + x^3):dydx=y(1x2)(x+x3).\frac{dy}{dx} = \frac{y(1 - x^2)}{(x + x^3)}.
  9. Solve for dydx\frac{dy}{dx}: We have found the derivative of the given equation with respect to xx, which is dydx=y(1x2)(x+x3)\frac{dy}{dx} = \frac{y(1 - x^2)}{(x + x^3)}.

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