Apply Quotient Rule: Use the quotient rule for differentiation, which is (v(u′)−u(v′))/(v2), where u=2x and v=x2+3.
Differentiate u: Differentiate u=2x with respect to x to get u′=2.
Differentiate v: Differentiate v=x2+3 with respect to x. First, rewrite v as (x2+3)21 to make it easier.
Use Chain Rule: Now, use the chain rule to differentiate v. The derivative of the outer function with respect to the inner function (x2+3) is (21)(x2+3)−21. Then multiply by the derivative of the inner function, which is 2x. So, v′=(21)(x2+3)−21⋅2x.
Apply Quotient Rule: Now apply the quotient rule: (v(u′)−u(v′))/(v2). Plug in u, u′, v, and v′ to get [(x2+3)(2)−(2x)(21(x2+3)−21⋅2x)]/(x2+3)2.
Simplify Numerator: Simplify the numerator: [2x2+3−(2x)(x2+3x)].
Simplify Denominator: Simplify the denominator: (x2+3)2 is just x2+3.
Combine Terms: Now, combine the terms in the numerator: 2x2+3−x2+32x2.
Write Final Derivative: Write the final simplified derivative: x2+32x2+3−x2+32x2.
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