Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

{[c(1)=56],[c(n)=c(n-1)*(1)/(2)]:}
What is the 
4^("th ") term in the sequence?

{c(1)=56c(n)=c(n1)12 \left\{\begin{array}{l} c(1)=56 \\ c(n)=c(n-1) \cdot \frac{1}{2} \end{array}\right. \newlineWhat is the 4th  4^{\text {th }} term in the sequence?

Full solution

Q. {c(1)=56c(n)=c(n1)12 \left\{\begin{array}{l} c(1)=56 \\ c(n)=c(n-1) \cdot \frac{1}{2} \end{array}\right. \newlineWhat is the 4th  4^{\text {th }} term in the sequence?
  1. Sequence Definition: Understand the sequence definition.\newlineThe sequence is defined recursively, with the first term c(1)c(1) given as 5656 and each subsequent term c(n)c(n) being half of the previous term c(n1)c(n-1). This is a geometric sequence with a common ratio of 12\frac{1}{2}.
  2. Calculate Second Term: Calculate the second term using the recursive formula.\newlineTo find the second term, we use the first term and multiply it by the common ratio.\newlinec(2)=c(1)×(12)=56×(12)=28c(2) = c(1) \times \left(\frac{1}{2}\right) = 56 \times \left(\frac{1}{2}\right) = 28
  3. Calculate Third Term: Calculate the third term using the recursive formula.\newlineTo find the third term, we use the second term and multiply it by the common ratio.\newlinec(3)=c(2)×(12)=28×(12)=14c(3) = c(2) \times \left(\frac{1}{2}\right) = 28 \times \left(\frac{1}{2}\right) = 14
  4. Calculate Fourth Term: Calculate the fourth term using the recursive formula.\newlineTo find the fourth term, we use the third term and multiply it by the common ratio.\newlinec(4)=c(3)×(12)=14×(12)=7c(4) = c(3) \times \left(\frac{1}{2}\right) = 14 \times \left(\frac{1}{2}\right) = 7

More problems from Geometric sequences