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{[c(1)=-20],[c(n)=c(n-1)+10]:} Find the 2^("nd ") term in the sequence.

{c(1)=−20c(n)=c(n−1)+10 \left\{\begin{array}{l} c(1)=-20 \\ c(n)=c(n-1)+10 \end{array}\right. \newlineFind the 2nd  2^{\text {nd }} term in the sequence.

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Full solution

Q. {c(1)=−20c(n)=c(n−1)+10 \left\{\begin{array}{l} c(1)=-20 \\ c(n)=c(n-1)+10 \end{array}\right. \newlineFind the 2nd  2^{\text {nd }} term in the sequence.
  1. Define Recursive Sequence: The sequence is defined recursively, with the first term given as c(1)=−20c(1) = -20. To find the second term, we need to apply the recursive formula c(n)=c(n−1)+10c(n) = c(n-1) + 10 to the first term.\newlineCalculation: c(2)=c(1)+10=−20+10=−10c(2) = c(1) + 10 = -20 + 10 = -10
  2. Calculate Second Term: We have found the second term in the sequence without any complications or errors.

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