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(b) Does 
(-4,10) satisfy the equation 
(3)/(2)x+y-4=0 ?
Yes
No

(b) Does (4,10) (-4,10) satisfy the equation 32x+y4=0 \frac{3}{2} x+y-4=0 ?\newlineYes\newlineNo

Full solution

Q. (b) Does (4,10) (-4,10) satisfy the equation 32x+y4=0 \frac{3}{2} x+y-4=0 ?\newlineYes\newlineNo
  1. Substitute values and calculate: Substitute the xx and yy values from the point (4,10)(-4,10) into the equation 32x+y4=0\frac{3}{2}x + y - 4 = 0.\newlineCalculation: 32(4)+104\frac{3}{2}(-4) + 10 - 4\newlineMath error check:
  2. Multiply first term by 4-4: Multiply (32)(\frac{3}{2}) by 4-4 to find the value of the first term.\newlineCalculation: (32)×4=6(\frac{3}{2}) \times -4 = -6\newlineMath error check:
  3. Add and subtract to find result: Add the result from Step 22 to the y-value from the point, which is 1010, and then subtract 44.\newlineCalculation: 6+104-6 + 10 - 4\newlineMath error check:
  4. Perform final check: Perform the addition and subtraction from Step 33 to determine if the result equals 00.\newlineCalculation: 6+104=0-6 + 10 - 4 = 0\newlineMath error check:
  5. Verify final result: Check if the final result from Step 44 is equal to 00, which would mean the point satisfies the equation.\newlineCalculation: 0=00 = 0\newlineMath error check:

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