Q. {b(1)=15b(n)=b(n−1)⋅(−3)What is the 4th term in the sequence?
Given information: We are given the first term of the sequence, b(1)=15, and a recursive formula for the sequence, b(n)=b(n−1)×(−3). To find the 4th term, we need to apply the recursive formula three times starting from the first term.
Find second term: First, we find the second term using the recursive formula. The second term is b(2)=b(1)×(−3).Calculation: b(2)=15×(−3)=−45.
Find third term: Next, we find the third term using the recursive formula. The third term is b(3)=b(2)×(−3).Calculation: b(3)=−45×(−3)=135.
Find fourth term: Finally, we find the fourth term using the recursive formula. The fourth term is b(4)=b(3)×(−3).Calculation: b(4)=135×(−3)=−405.