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{[a(1)=-2],[a(n)=a(n-1)-5]:}
Find the 
4^("th ") term in the sequence.

{a(1)=2a(n)=a(n1)5 \left\{\begin{array}{l} a(1)=-2 \\ a(n)=a(n-1)-5 \end{array}\right. \newlineFind the 4th  4^{\text {th }} term in the sequence.

Full solution

Q. {a(1)=2a(n)=a(n1)5 \left\{\begin{array}{l} a(1)=-2 \\ a(n)=a(n-1)-5 \end{array}\right. \newlineFind the 4th  4^{\text {th }} term in the sequence.
  1. Identify first term and common difference: Identify the first term and the common difference in the sequence.\newlineThe first term a(1)a(1) is given as 2-2.\newlineThe common difference is the amount subtracted from each term to get the next, which is 5-5.
  2. Calculate second term: Calculate the second term using the recursive formula.\newlineThe second term a(2)a(2) is a(1)5a(1) - 5.\newlinea(2)=25=7a(2) = -2 - 5 = -7.
  3. Calculate third term: Calculate the third term using the recursive formula.\newlineThe third term a(3)a(3) is a(2)5a(2) - 5.\newlinea(3)=75=12a(3) = -7 - 5 = -12.
  4. Calculate fourth term: Calculate the fourth term using the recursive formula.\newlineThe fourth term a(4)a(4) is a(3)5a(3) - 5.\newlinea(4)=125=17a(4) = -12 - 5 = -17.

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