[H+]=10−pHpH is a measure of the hydrogen ion concentration, [H+], measured in moles per liter, of a solution. Solutions with a high concentration of hydrogen ions have a low pH and solutions with a low concentration of hydrogen ions have a high pH. The relationship between [H+]and pH is shown in the equation. What is the effect on pH if the hydrogen ion concentration is multiplied by 10 ?Choose 1 answer:(A) The pH increases by 1 .(B) The pH is multiplied by 10.(C) The pH is divided by 10 .(D) The pH decreases by 1 .
Q. [H+]=10−pHpH is a measure of the hydrogen ion concentration, [H+], measured in moles per liter, of a solution. Solutions with a high concentration of hydrogen ions have a low pH and solutions with a low concentration of hydrogen ions have a high pH. The relationship between [H+]and pH is shown in the equation. What is the effect on pH if the hydrogen ion concentration is multiplied by 10 ?Choose 1 answer:(A) The pH increases by 1 .(B) The pH is multiplied by 10.(C) The pH is divided by 10 .(D) The pH decreases by 1 .
Understanding pH and [H(+)]: Understand the relationship between [H(+)] and pH.The equation [H(+)]=10−pH shows that the pH is the negative logarithm (base 10) of the hydrogen ion concentration. This means that if the hydrogen ion concentration increases, the pH value decreases, and vice versa.
Effect of Multiplying [H+]:</b>Determinetheeffectofmultiplying$[H+] by 10.If the hydrogen ion concentration [H+] is multiplied by 10, the new concentration becomes 10×[H+]. We need to find out how this affects the pH.
Applying the Change to the Equation: Apply the change to the equation.The new hydrogen ion concentration is 10×[H+], so we substitute this into the equation:[H+]′=10×[H+]=10×10−pH=101×10−pH=101−pH
Finding the New pH Value: Find the new pH value.To find the new pH, we take the negative logarithm (base 10) of the new hydrogen ion concentration:pH' = −log([H+]′)=−log(101−pH)=1−pH
Calculating the Change in pH: Calculate the change in pH.The change in pH is the difference between the new pH and the original pH:ΔpH=pH′−pH=(1−pH)−pH=1−2pHSince we are only multiplying [H(+)] by 10 once, the change in pH is simply 1 unit. Therefore, the pH decreases by 1.
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