Q. (−9x2+3x+9)−(−2x2+3x−2)=ax2+bx+cwhere a,b, and c are constants. What is the value of b ?Choose 1 answer:(A) −7(B) 6(C) 0(D) 11
Distribute negative sign: First, we need to distribute the negative sign to the terms inside the second set of parentheses.(−9x2+3x+9)−(−2x2+3x−2)= (−9x2+3x+9)+(2x2−3x+2)
Combine like terms: Next, we combine like terms by adding the coefficients of the x2 terms, the x terms, and the constant terms separately.(−9x2+2x2)+(3x−3x)+(9+2)=−7x2+0x+11
Identify coefficients: Now we can identify the coefficients a, b, and c in the expression ax2+bx+c.$a=−7, b=0, c=11\)
Find value of b: We are asked to find the value of b. From our previous step, we have determined that b=0.
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