Q. 7y2=50x−150y=23−xIf x1,y1 and x2,y2 are distinct solutions to the system of equations shown, what is the product of the y1 and y2 ?◻
Substitute and solve for x: Substitute y from the second equation into the first equation to eliminate y and solve for x.7y2=50x−150 becomes 7((3−x)/2)2=50x−150.
Expand and simplify: Expand and simplify the equation. 47(9−6x+x2)=50x−150.
Clear the fraction: Multiply both sides by 4 to clear the fraction.7(9−6x+x2)=200x−600.
Distribute and simplify: Distribute the 7 on the left side.63−42x+7x2=200x−600.
Move terms and set to zero: Move all terms to one side to set the equation to zero.7x2−42x−200x+63+600=0.
Combine like terms: Combine like terms. 7x2−242x+663=0.
Factor the quadratic equation: Factor the quadratic equation.(7x−221)(x−3)=0.
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