Q. 5.2s+0.1r=00.7(r+0.2)+3.2=−3sIf (r,s) is the solution to the system of equations, what is the value of s−r ?
Equation 1: We have the system of equations:5.2s+0.1r=00.7(r+0.2)+3.2=−3sLet's solve the first equation for r.
Expressing r in terms of s: From the first equation, we can express r in terms of s:0.1r=−5.2sr=−52s
Substituting r into Equation 2: Now let's substitute r=−52s into the second equation:0.7(−52s+0.2)+3.2=−3s
Distributing and combining terms: Distribute 0.7 into the parentheses:0.7×−52s+0.7×0.2+3.2=−3s−36.4s+0.14+3.2=−3s
Isolating s: Combine like terms:−36.4s+3.34=−3s
Solving for s: Add 36.4s to both sides to isolate s:3.34=33.4s
Calculating r: Divide both sides by 33.4 to solve for s: s=33.43.34
Calculating s−r: Calculate the value of s:s=0.1
Final answer: Now that we have the value of s, let's find r using r=−52s:r=−52×0.1
Final answer: Now that we have the value of s, let's find r using r=−52s: r=−52×0.1Calculate the value of r: r=−5.2
Final answer: Now that we have the value of s, let's find r using r=−52s: r=−52×0.1Calculate the value of r: r=−5.2Finally, calculate s−r: s−r=0.1−(−5.2)
Final answer: Now that we have the value of s, let's find r using r=−52s: r=−52×0.1Calculate the value of r: r=−5.2Finally, calculate s−r: s−r=0.1−(−5.2)Perform the subtraction: s−r=0.1+5.2
Final answer: Now that we have the value of s, let's find r using r=−52s: r=−52×0.1Calculate the value of r: r=−5.2Finally, calculate s−r: s−r=0.1−(−5.2)Perform the subtraction: s−r=0.1+5.2Calculate the final answer: s−r=5.3