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Let’s check out your problem:

(-4x^(3)*x^(2)y^(4))/(-2x^(3)y^(4))

−4x3⋅x2y4−2x3y4 \frac{-4 x^{3} \cdot x^{2} y^{4}}{-2 x^{3} y^{4}} =

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Full solution

Q. −4x3⋅x2y4−2x3y4 \frac{-4 x^{3} \cdot x^{2} y^{4}}{-2 x^{3} y^{4}} =
  1. Factorize Numerator and Denominator: First, let's factorize the numerator and the denominator.\newlineNumerator: −4x3⋅x2⋅y4=−4x3+2y4=−4x5y4-4x^{3}\cdot x^{2}\cdot y^{4} = -4x^{3+2}y^{4} = -4x^{5}y^{4}\newlineDenominator: −2x3y4-2x^{3}y^{4}
  2. Simplify by Dividing: Next, simplify the expression by dividing the numerator by the denominator.\newline(−4x5y4)/(−2x3y4)=(4/2)⋅(x5−3)⋅(y4−4)(-4x^{5}y^{4})/(-2x^{3}y^{4}) = (4/2)\cdot(x^{5-3})\cdot(y^{4-4})\newline=2x2y0= 2x^{2}y^{0}
  3. Further Simplification: Since y0y^{0} equals 11, we can simplify further:\newline2x2⋅1=2x22x^{2}\cdot1 = 2x^{2}

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