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$(4r^2-3r+2) -(-r^2-3r)=$

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Find trigonometric ratios using reference angles

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Q.

(4r^2-3r+2) -(-r^2-3r)=

Distribute Negative Sign: Distribute the negative sign to the terms inside the parentheses. $\newline$ To subtract the polynomial $-(-r^2-3r)$ , we need to distribute the negative sign to each term inside the parentheses, which changes the signs of the terms. $\newline$ So, $-(-r^2)$ becomes $+r^2$ and $-(-3r)$ becomes $+3r$ .
Combine Like Terms: Combine like terms. $\newline$ Now we combine the like terms from the expression $(4r^2-3r+2) + (r^2+3r)$ . $\newline$ $4r^2 + r^2 = 5r^2$ (combining like terms for $r^2$ ) $\newline$ $-3r + 3r = 0$ (combining like terms for $r$ ) $\newline$ The constant term remains as $+2$ .
Write Final Expression: Write the final simplified expression. $\newline$ Since $-3r$ and $+3r$ cancel each other out, we are left with: $\newline$ $5r^2 + 2$ $\newline$ This is the simplified form of the given expression.

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