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Evaluate: −40+(−1)−(2)×6÷3−2- 40 +{ (-1)- (2)} \times 6 \div{ 3-2}

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Full solution

Q. Evaluate: −40+(−1)−(2)×6÷3−2- 40 +{ (-1)- (2)} \times 6 \div{ 3-2}
  1. Calculate Parentheses: Calculate the expression inside the first set of parentheses.\newline(−1)−(2)=−1−2=−3(-1) - (2) = -1 - 2 = -3
  2. Calculate Subtraction: Calculate the expression inside the second set of parentheses.\newline3−2=13 - 2 = 1
  3. Perform Division: Perform the division next according to the order of operations (PEMDAS/BODMAS).(−3)×6÷1=(−3)×6=−18(-3) \times 6 \div 1 = (-3) \times 6 = -18
  4. Add Result: Finally, add the result to −40-40.−40+(−18)=−40−18=−58-40 + (-18) = -40 - 18 = -58

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