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An amusement park is unveiling 5 brand-new rides. In how many different orders can the new rides be unveiled?
◻ orders

An amusement park is unveiling 55 brand-new rides. In how many different orders can the new rides be unveiled?\newline \square orders

Full solution

Q. An amusement park is unveiling 55 brand-new rides. In how many different orders can the new rides be unveiled?\newline \square orders
  1. Understand the problem: Understand the problem.\newlineWe need to find the number of different orders in which 55 new rides can be unveiled. This is a permutation problem because the order in which the rides are unveiled matters.
  2. Recall the formula: Recall the formula for permutations.\newlineThe number of permutations of nn distinct objects is n!n!, which means nn factorial. For 55 rides, we need to calculate 5!5! (55 factorial).
  3. Calculate 55 factorial: Calculate 55 factorial.\newline5!=5×4×3×2×15! = 5 \times 4 \times 3 \times 2 \times 1\newline5!=1205! = 120
  4. Conclude the solution: Conclude the solution.\newlineThe number of different orders in which the 55 rides can be unveiled is 120120.

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