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-4+bx=2x+3(x+1)
In the equation shown, 
b is a constant. For what value of 
b does the equation have no solutions?
Choose 1 answer:
(A) 3
(B) 4
(c) 5
(D) 6

4+bx=2x+3(x+1)-4+bx=2x+3(x+1)\newlineIn the equation shown, \newlinebb is a constant. For what value of \newlinebb does the equation have no solutions?\newlineChoose 11 answer:\newline(A) 33\newline(B) 44\newline(C) 55\newline(D) 66

Full solution

Q. 4+bx=2x+3(x+1)-4+bx=2x+3(x+1)\newlineIn the equation shown, \newlinebb is a constant. For what value of \newlinebb does the equation have no solutions?\newlineChoose 11 answer:\newline(A) 33\newline(B) 44\newline(C) 55\newline(D) 66
  1. Distribute and Simplify: First, we need to simplify the right side of the equation by distributing the 33 into the parentheses.\newlineCalculation: 2x+3(x+1)=2x+3x+32x + 3(x + 1) = 2x + 3x + 3\newlineSimplified: 2x+3x+3=5x+32x + 3x + 3 = 5x + 3
  2. Rearrange Terms: Next, we want to bring all terms involving xx to one side of the equation and constants to the other side to compare the coefficients of xx.
    Calculation: 4+bx=5x+3-4 + bx = 5x + 3
    Rearrange: bx5x=3+4bx - 5x = 3 + 4
    Simplified: (b5)x=7(b - 5)x = 7
  3. Find Coefficient of xx: For the equation to have no solutions, the coefficient of xx on both sides must be different, and the constants must be the same. Since there is no constant on the left side, we need the coefficient of xx to be zero.\newlineCalculation: b5=0b - 5 = 0\newlineSolve for bb: b=5b = 5
  4. Determine No Solutions: We have found the value of bb that makes the coefficient of xx on both sides of the equation equal, which would normally mean the equation has infinitely many solutions. However, since the constants are different (77 on the right side and none on the left), the equation has no solutions.

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