-4(2x^(2)-3)=-8x^(2)+c In the given equation, c is a constant. What is the value of c ?

Distribute -4: First, distribute the -4 across the terms inside the parentheses to simplify the left side of the equation. -4 * 2x^(2) = -8x^(2) -4 * (-3) = 12 So, the equation becomes -8x^(2) + 12 = -8x^(2) + cCancel out x^2 terms: Next, since the x^2 terms on both sides of the equation are the same but with opposite signs, they cancel each other out. This leaves us with the equation 12 = c.Find the value of c: Now, we can see that the constant c is equal to 12, as that is the remaining term in the equation after canceling out the x^2 terms.

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-4(2x^(2)-3)=-8x^(2)+c
In the given equation,
c is a constant. What is the value of
c ?

$-4\left(2 x^{2}-3\right)=-8 x^{2}+c$ $\newline$ In the given equation, $c$ is a constant. What is the value of $c$ ?

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Algebra 2

Find trigonometric ratios using multiple identities

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-4\left(2 x^{2}-3\right)=-8 x^{2}+c

\newline

In the given equation,

c

is a constant. What is the value of

c

Distribute $-4$ : First, distribute the $-4$ across the terms inside the parentheses to simplify the left side of the equation. $\newline$ $-4\left(2 x^{2}-3\right)=-8 x^{2}+c$ $\newline$ $-4 \times 2x^{2} = -8x^{2}$ $\newline$ $-4 \times (-3) = 12$ $\newline$ So, the equation becomes $-8x^{2} + 12 = -8x^{2} + c$ .
Cancel out $x^2$ terms: Next, since the $x^2$ terms on both sides of the equation are the same, they cancel each other out. $\newline$ This leaves us with the equation $12 = c$ .
Find the value of $c$ : We have, $12 = c$ . $\newline$ Therefore, the value of $c$ is $12$ .