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(3g-4)(2g-8)=ag^(2)+bg+c
In the given equation,
a,b, and
c are constants. What is the value of
a ?
Choose 1 answer:
(A) -32
(B) -16
(C) 5
(D) 6

$(3 g-4)(2 g-8)=a g^{2}+b g+c$ $\newline$ In the given equation, $a, b$ , and $c$ are constants. What is the value of $a$ ? $\newline$ Choose $1$ answer: $\newline$ (A) $-32$ $\newline$ (B) $-16$ $\newline$ (C) $5$ $\newline$ (D) $6$

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Write a quadratic function from its x-intercepts and another point

Full solution

Q.

(3 g-4)(2 g-8)=a g^{2}+b g+c

\newline

In the given equation,

a, b

, and

c

are constants. What is the value of

a

?

\newline

Choose

1

answer:

\newline

(A)

-32

\newline

(B)

-16

\newline

(C)

5

\newline

(D)

6

Expand Expression: We need to expand the expression $(3g-4)(2g-8)$ to find the coefficient of the $g^2$ term, which will give us the value of $a$ . Expanding the expression using the distributive property (also known as the FOIL method for binomials): $(3g-4)(2g-8) = 3g \times 2g + 3g \times (-8) + (-4) \times 2g + (-4) \times (-8)$
Perform Multiplication: Now we perform the multiplication for each term: $\newline$ $3g \times 2g = 6g^2$ $\newline$ $3g \times (-8) = -24g$ $\newline$ $(-4) \times 2g = -8g$ $\newline$ $(-4) \times (-8) = 32$
Combine Like Terms: Combine the like terms to get the expanded form: $\newline$ $6g^2 - 24g - 8g + 32$ $\newline$ $6g^2 - 32g + 32$
Find Coefficient: From the expanded form, we can see that the coefficient of $g^2$ is $6$ . This is the value of $a$ .

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