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f(x)=x+2x+1+x+3 f(x) = |x + 2| - |x + 1| + x + 3

Full solution

Q. f(x)=x+2x+1+x+3 f(x) = |x + 2| - |x + 1| + x + 3
  1. Substitute x=0x = 0: Substitute the value of x=0x = 0 into the function f(x)f(x).f(0)=0+20+1+0+3f(0) = |0 + 2| - |0 + 1| + 0 + 3
  2. Simplify absolute values: Simplify the expression by calculating the absolute values. f(0)=21+0+3f(0) = |2| - |1| + 0 + 3
  3. Calculate arithmetic operations: Since the absolute value of a positive number is the number itself, we have: f(0)=21+0+3f(0) = 2 - 1 + 0 + 3
  4. Find final value: Perform the arithmetic operations.\newlinef(0)=1+3f(0) = 1 + 3
  5. Find final value: Perform the arithmetic operations.\newlinef(0)=1+3f(0) = 1 + 3 Add the numbers to find the final value.\newlinef(0)=4f(0) = 4

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