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-3(ax^(2)-2y^(2))=-21x^(2)+6y^(2)
In the given equation, 
a is a constant. What is the value of 
a ?

3(ax22y2)=21x2+6y2 -3\left(a x^{2}-2 y^{2}\right)=-21 x^{2}+6 y^{2} \newlineIn the given equation, a a is a constant. What is the value of a a ?

Full solution

Q. 3(ax22y2)=21x2+6y2 -3\left(a x^{2}-2 y^{2}\right)=-21 x^{2}+6 y^{2} \newlineIn the given equation, a a is a constant. What is the value of a a ?
  1. Distribute 3-3: We are given the equation 3(ax22y2)=21x2+6y2-3(a x^{2}-2 y^{2})=-21 x^{2}+6 y^{2}. To find the value of aa, we need to simplify and compare the coefficients of like terms on both sides of the equation.
  2. Simplify equation: First, distribute the 3-3 on the left side of the equation to both terms inside the parentheses.\newline3(ax2)+3(2y2)=21x2+6y2-3(ax^{2}) + 3(2y^{2}) = -21x^{2} + 6y^{2}\newlineThis simplifies to 3ax2+6y2=21x2+6y2-3ax^{2} + 6y^{2} = -21x^{2} + 6y^{2}.
  3. Compare x2x^2 coefficients: Now, compare the coefficients of x2x^2 on both sides of the equation. On the left side, we have 3a-3a, and on the right side, we have 21-21.\newlineSo, 3a=21-3a = -21.
  4. Divide by 3-3: To find the value of aa, divide both sides of the equation by 3-3.\newlinea=213a = \frac{-21}{-3}.
  5. Find value of a: Perform the division to find the value of aa. \newlinea=7a = 7.

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