Q. −3(ax2−2y2)=−21x2+6y2In the given equation, a is a constant. What is the value of a ?
Distribute −3: We are given the equation −3(ax2−2y2)=−21x2+6y2. To find the value of a, we need to simplify and compare the coefficients of like terms on both sides of the equation.
Simplify equation: First, distribute the −3 on the left side of the equation to both terms inside the parentheses.−3(ax2)+3(2y2)=−21x2+6y2This simplifies to −3ax2+6y2=−21x2+6y2.
Compare x2 coefficients: Now, compare the coefficients of x2 on both sides of the equation. On the left side, we have −3a, and on the right side, we have −21.So, −3a=−21.
Divide by −3: To find the value of a, divide both sides of the equation by −3.a=−3−21.
Find value of a: Perform the division to find the value of a. a=7.
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