{:[2x-1=y],[3x-1=y]:} Consider the given system of equations. Which of the following statements about this system is true? Choose 1 answer: A There is only one (x,y) solution and y is positive. (B) There is only one (x,y) solution and y is negative. (C) There are infinitely many (x,y) solutions. (D) There are no (x,y) solutions.

Question

{:[2x-1=y],[3x-1=y]:} Consider the given system of equations. Which of the following statements about this system is true? Choose 1 answer: A There is only one  (x,y) solution and  y is positive. (B) There is only one  (x,y) solution and  y is negative. (C) There are infinitely many  (x,y) solutions. (D) There are no  (x,y) solutions.

Bytelearn · Accepted Answer

Analyze System of Equations: Analyze the given system of equations. We have the system: 2x - 1 = y 3x - 1 = y We need to determine the nature of the solutions to this system.Compare Equations: Compare the two equations. Both equations are equal to y, so we can set them equal to each other: 2x - 1 = 3x - 1Solve for x: Solve for x. Subtract 2x from both sides to get: -1 = x - 1 Now, add 1 to both sides to find the value of x: 0 = xSubstitute for y: Substitute x back into one of the original equations to find y. Using the first equation: 2x - 1 = y 2(0) - 1 = y y = -1Conclude Solution: Conclude the nature of the solution. Since we found a single solution for x and y, there is only one (x,y) solution. The value of y is negative.

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