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$-20x^2+25x^2y-40x=-5x(4x-5xy+c)$ what is value of $c$

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Factor by grouping

Full solution

Q.

-20x^2+25x^2y-40x=-5x(4x-5xy+c)

what is value of

c

Distribute $-5x$ : First, let's distribute the $-5x$ across the terms inside the parentheses on the right side of the equation to see if it matches the left side. $\newline$ $-5x \times 4x = -20x^2$ $\newline$ $-5x \times -5xy = 25x^2y$ $\newline$ Now we need to find the value of $c$ such that $-5x \times c = -40x$ .
Find value of c: To find the value of c, we set up the equation $-5x \cdot c = -40x$ . $\newline$ Now we divide both sides by $-5x$ to solve for c. $\newline$ $c = \frac{-40x}{-5x}$ $\newline$ $c = 8$

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