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20x2+25x2y40x=5x(4x5xy+c)-20x^{2} + 25x^{2}y - 40x = -5x(4x - 5xy + c)\newlineWhat is the value of c?

Full solution

Q. 20x2+25x2y40x=5x(4x5xy+c)-20x^{2} + 25x^{2}y - 40x = -5x(4x - 5xy + c)\newlineWhat is the value of c?
  1. Distribute Terms: Distribute 5x-5x across the terms inside the parentheses on the right side of the equation.\newline5x×4x=20x2-5x \times 4x = -20x^2\newline5x×5xy=25x2y-5x \times -5xy = 25x^2y\newline5x×c=5xc-5x \times c = -5xc
  2. Compare Distributed Terms: Compare the distributed terms with the corresponding terms on the left side of the equation.\newlineThe term 20x2-20x^2 on the left matches the term 20x2-20x^2 on the right.\newlineThe term 25x2y25x^2y on the left matches the term 25x2y25x^2y on the right.\newlineThe term 40x-40x on the left should match the term 5xc-5xc on the right.
  3. Set Equation Equal: Set the unmatched terms equal to each other to solve for cc.40x=5xc-40x = -5xc
  4. Divide to Solve: Divide both sides of the equation by 5x-5x to solve for cc.c=40x5xc = \frac{-40x}{-5x}
  5. Simplify for cc: Simplify the equation to find the value of cc.c=8c = 8