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$-20x^2+25x^2y-40x=-5x(4x-5xy+c)$ Solve for $c$

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Full solution

Q.

-20x^2+25x^2y-40x=-5x(4x-5xy+c)

Solve for

c

Distribute $-5x$ : Step Title: Distribute the $-5x$ across the parentheses $\newline$ Concise Step Description: Multiply $-5x$ by each term inside the parentheses to expand the right side of the equation. $\newline$ Step Calculation: $-5x \times 4x = -20x^2$ , $-5x \times -5xy = 25x^2y$ , $-5x \times c = -5xc$ $\newline$ Step Output: $-20x^2 + 25x^2y - 5xc$
Compare terms: Step Title: Compare the expanded equation to the original $\newline$ Concise Step Description: Compare the terms on the right side of the expanded equation to the terms on the left side of the original equation to find the value of $c$ . $\newline$ Step Calculation: The terms $-20x^2$ and $25x^2y$ match on both sides, so we compare the remaining terms $-40x$ and $-5xc$ . $\newline$ Step Output: $-40x = -5xc$
Solve for $c$ : Step Title: Solve for $c$ $\newline$ Concise Step Description: Divide both sides of the equation by $-5x$ to isolate $c$ . $\newline$ Step Calculation: $(-40x) / (-5x) = (-5xc) / (-5x)$ $\newline$ Step Output: $c = 8$

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