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- π2≤θ≤π2\frac{\pi}{2} \leq \theta \leq \frac{\pi}{2}. Find the value of θ\theta in radians.\newlineθ=0\theta = 0\newlineWrite your answer in simplified, rationalized form. Do not round.\newlineθ=\theta = ______

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Inverses of sin, cos, and tan: radiansright chevron icon

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Q. - π2≤θ≤π2\frac{\pi}{2} \leq \theta \leq \frac{\pi}{2}. Find the value of θ\theta in radians.\newlineθ=0\theta = 0\newlineWrite your answer in simplified, rationalized form. Do not round.\newlineθ=\theta = ______
  1. Identify Sine Zero Angle: Identify the angle where the value of sine is 00 within the given interval.sin⁡(θ)=0\sin(\theta) = 0 at θ=0,π,−π,2π\theta = 0, \pi, -\pi, 2\pi, etc. But we only consider the interval −π/2≤θ≤π/2- \pi /2 \leq \theta \leq \pi /2.
  2. Choose Theta Value: Choose the value of θ\theta that falls within the given interval.θ=0\theta = 0 is the only value that falls within the interval −π2≤θ≤π2- \frac{\pi}{2} \leq \theta \leq \frac{\pi}{2}.

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