-2(1)/(4)÷(-3(1)/(3))=

Convert to Improper Fractions: First, let's convert the mixed numbers to improper fractions. -2(1)/(4) becomes -9/4 and -3(1)/(3) becomes -10/3.Divide Fractions: Now, we divide the fractions by multiplying the first fraction by the reciprocal of the second fraction. So, (-9/4) ÷ (-10/3) becomes (-9/4) * (-3/10).Multiply Numerators and Denominators: Next, we multiply the numerators and the denominators. (-9) * (-3) = 27 and 4 * 10 = 40. So, (-9/4) * (-3/10) = 27/40.Simplify Fraction: Finally, we simplify the fraction if possible. 27/40 cannot be simplified further, so that's our answer.

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Math Problems

Grade 8

Powers with negative bases

Full solution

-2 \frac{1}{4} \div\left(-3 \frac{1}{3}\right)=

Convert to Improper Fractions: First, let's convert the mixed numbers to improper fractions. $\newline$ $-2\frac{1}{4}$ becomes $-\frac{9}{4}$ and $-3\frac{1}{3}$ becomes $-\frac{10}{3}$ .
Divide Fractions: Now, we divide the fractions by multiplying the first fraction by the reciprocal of the second fraction. $\newline$ So, $(-\frac{9}{4}) \div (-\frac{10}{3})$ becomes $(-\frac{9}{4}) \times (-\frac{3}{10})$ .
Multiply Numerators and Denominators: Next, we multiply the numerators and the denominators. $\newline$ $(-9) \times (-3) = 27$ and $4 \times 10 = 40$ . $\newline$ So, $(-\frac{9}{4}) \times (-\frac{3}{10}) = \frac{27}{40}$ .
Simplify Fraction: Finally, we simplify the fraction if possible. $\frac{27}{40}$ cannot be simplified further, so that's our answer.