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(10i)+(40+8i)(-10i)+(-40+8i)\newlineExpress your answer in the form (a+bi).(a+bi).

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Q. (10i)+(40+8i)(-10i)+(-40+8i)\newlineExpress your answer in the form (a+bi).(a+bi).
  1. Addition of Complex Numbers: We need to add the complex numbers (10i)(-10i) and (40+8i)(-40 + 8i) together.\newlineCalculation: (10i)+(40+8i)=40+(10i+8i)=402i(-10i) + (-40 + 8i) = -40 + (-10i + 8i) = -40 - 2i
  2. Calculation of Sum: Now we need to find the conjugate of the result, which is 402i-40 - 2i. The conjugate of a complex number a+bia + bi is abia - bi. Calculation: The conjugate of 402i-40 - 2i is 40+2i-40 + 2i.

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