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/_1 and 
/_2 are vertical angles. If 
m/_1=(x+18)^(@) and 
m/_2=(4x-24)^(@), then find the measure of 
/_1.
Answer:

1 \angle 1 and 2 \angle 2 are vertical angles. If m1=(x+18) \mathrm{m} \angle 1=(x+18)^{\circ} and m2=(4x24) \mathrm{m} \angle 2=(4 x-24)^{\circ} , then find the measure of 1 \angle 1 .\newlineAnswer:

Full solution

Q. 1 \angle 1 and 2 \angle 2 are vertical angles. If m1=(x+18) \mathrm{m} \angle 1=(x+18)^{\circ} and m2=(4x24) \mathrm{m} \angle 2=(4 x-24)^{\circ} , then find the measure of 1 \angle 1 .\newlineAnswer:
  1. Vertical angles congruent: Vertical angles are congruent, so their measures are equal. We can set the expressions for the measures of angle 11 and angle 22 equal to each other to find the value of xx.m/1=m/2m/\angle1 = m/\angle2(x+18)=(4x24)(x + 18)^\circ = (4x - 24)^\circ
  2. Set expressions equal: Solve the equation for xx by first subtracting xx from both sides to get the xx terms on one side.\newline(4x24)x=(x+18)x(4x - 24)^\circ - x = (x + 18)^\circ - x\newline3x24=183x - 24 = 18
  3. Solve for x: Next, add 2424 to both sides to isolate the term with xx.\newline3x24+24=18+243x - 24 + 24 = 18 + 24\newline3x=423x = 42
  4. Isolate x term: Divide both sides by 33 to solve for x.\newline3x3=423\frac{3x}{3} = \frac{42}{3}\newlinex=14x = 14
  5. Substitute x value: Now that we have the value of xx, we can substitute it back into the expression for m/1m/\angle1 to find the measure of angle 11.\newlinem/1=(x+18)m/\angle1 = (x + 18)^\circ\newlinem/1=(14+18)m/\angle1 = (14 + 18)^\circ\newlinem/1=32m/\angle1 = 32^\circ

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