/_1 and /_2 are vertical angles. If m/_1=(2x+20)^(@) and m/_2=(6x+4)^(@), then find the measure of /_2. Answer:

Vertical angles congruency: Vertical angles are congruent, so their measures are equal. Therefore, we can set the expressions for m/_1 and m/_2 equal to each other to find the value of x. m/_1 = m/_2 (2x + 20) = (6x + 4)Setting up equation: Now we will solve for x by subtracting 2x from both sides of the equation to get the x terms on one side. (2x + 20) - 2x = (6x + 4) - 2x 20 = 4x + 4Solving for x: Next, we subtract 4 from both sides to isolate the term with x. 20 - 4 = 4x + 4 - 4 16 = 4xIsolating x term: Now we divide both sides by 4 to solve for x. 16 / 4 = 4x / 4 x = 4Substitute x into m/_2: With the value of x found, we can now substitute it back into the expression for m/_2 to find the measure of /_2. m/_2 = 6x + 4 m/_2 = 6(4) + 4Calculate m/_2: We perform the multiplication and addition to find the measure of /_2. m/_2 = 24 + 4 m/_2 = 28

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/_1 and
/_2 are vertical angles. If
m/_1=(2x+20)^(@) and
m/_2=(6x+4)^(@), then find the measure of
/_2.
Answer:

$\angle 1$ and $\angle 2$ are vertical angles. If $\mathrm{m} \angle 1=(2 x+20)^{\circ}$ and $\mathrm{m} \angle 2=(6 x+4)^{\circ}$ , then find the measure of $\angle 2$ . $\newline$ Answer:

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Math Problems

Algebra 1

Transformations of quadratic functions

Full solution

\angle 1

and

\angle 2

are vertical angles. If

\mathrm{m} \angle 1=(2 x+20)^{\circ}

and

\mathrm{m} \angle 2=(6 x+4)^{\circ}

, then find the measure of

\angle 2

\newline

Answer:

Vertical angles congruency: Vertical angles are congruent, so their measures are equal. Therefore, we can set the expressions for $m/\_1$ and $m/\_2$ equal to each other to find the value of $x$ . $m/\_1 = m/\_2$ $(2x + 20) = (6x + 4)$
Setting up equation: Now we will solve for $x$ by subtracting $2x$ from both sides of the equation to get the $x$ terms on one side. $(2x + 20) - 2x = (6x + 4) - 2x$ $20 = 4x + 4$
Solving for x: Next, we subtract $4$ from both sides to isolate the term with $x$ . $\newline$ $20 - 4 = 4x + 4 - 4$ $\newline$ $16 = 4x$
Isolating x term: Now we divide both sides by $4$ to solve for $x$ . $\frac{16}{4} = \frac{4x}{4}$ $x = 4$
Substitute $x$ into $m/_{2}$ : With the value of $x$ found, we can now substitute it back into the expression for $m/_{2}$ to find the measure of $/_{2}$ .
$m/_{2} = 6x + 4$
$m/_{2} = 6(4) + 4$
Calculate $m/_{2}$ : We perform the multiplication and addition to find the measure of $/_{2}$ . $m/_{2} = 24 + 4$ $m/_{2} = 28$