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Math Problems
Precalculus
Introduction to partial sums
Solve for
z
z
z
. Express your answer as a proper or improper fraction in simplest terms.
\newline
1
8
=
−
1
2
z
+
1
6
\frac{1}{8}=-\frac{1}{2} z+\frac{1}{6}
8
1
=
−
2
1
z
+
6
1
\newline
Answer:
z
=
z=
z
=
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