Resources
Testimonials
Plans
Sign in
Sign up
Resources
Testimonials
Plans
Home
Math Problems
Grade 8
Write an equation word problem
Solve.
\newline
7
(
2
z
−
4
)
=
0
7(2 z-4)=0
7
(
2
z
−
4
)
=
0
\newline
Answer:
z
=
z=
z
=
\newline
Submit Answer
Get tutor help
Complete the recursive formula of the arithmetic sequence
\newline
4
,
22
,
40
,
58
,
…
4, 22, 40, 58, \dots
4
,
22
,
40
,
58
,
…
.
\newline
b
(
1
)
=
□
b(1)=\square
b
(
1
)
=
□
\newline
b
(
n
)
=
b
(
n
−
1
)
+
□
b(n) = b(n-1) +\square
b
(
n
)
=
b
(
n
−
1
)
+
□
Get tutor help
{
g
(
x
)
=
3
x
−
7
h
(
x
)
=
2
−
g
(
x
)
\begin{cases} g(x)=3x-7 \ h(x)=2-g(x) \end{cases}
{
g
(
x
)
=
3
x
−
7
h
(
x
)
=
2
−
g
(
x
)
\newline
The functions
g
g
g
and
h
h
h
are defined. What is the value of
h
(
1
)
h(1)
h
(
1
)
?
\newline
Choose
1
1
1
answer:
\newline
(A)
\text{(A)}
(A)
6
6
6
\newline
(B)
\text{(B)}
(B)
1
1
1
\newline
(C)
\text{(C)}
(C)
−
2
-2
−
2
\newline
(D)
\text{(D)}
(D)
−
6
-6
−
6
Get tutor help
{
6
5
p
+
k
q
=
4
5
q
=
3
5
p
−
2
5
\begin{cases} \frac{6}{5}p + kq = \frac{4}{5} \ q = \frac{3}{5}p - \frac{2}{5} \end{cases}
{
5
6
p
+
k
q
=
5
4
q
=
5
3
p
−
5
2
Consider the system of equations, where
k
k
k
is a constant. For which value of
k
k
k
is there no
(
p
,
q
)
(p,q)
(
p
,
q
)
solutions?
\newline
Choose
1
1
1
answer:
\newline
(A)
−
2
-2
−
2
\newline
(B)
0
0
0
\newline
(C)
2
2
2
\newline
(D) None of the above
Get tutor help
Which value of
k
k
k
makes
5
−
k
+
12
=
16
5-k+12=16
5
−
k
+
12
=
16
a true statement?
\newline
Choose
1
1
1
answer:
\newline
(A)
k
=
1
k=1
k
=
1
\newline
(B)
k
=
2
k=2
k
=
2
\newline
(C)
k
=
3
k=3
k
=
3
\newline
(D)
k
=
4
k=4
k
=
4
Get tutor help
Solve for
k
k
k
.
k
4
=
3
8
\frac{k}{4}=\frac{3}{8}
4
k
=
8
3
\newline
k
=
□
k=\square
k
=
□
Get tutor help
How many solutions does the system have?
\newline
{
y
=
−
7
x
+
8
y
=
−
7
x
−
8
\begin{cases} y = -7x + 8 \\ y = -7x - 8 \end{cases}
{
y
=
−
7
x
+
8
y
=
−
7
x
−
8
\newline
Choose
1
1
1
answer:
\newline
(A) Exactly one solution
\newline
(B) No solutions
\newline
(C) Infinitely many solutions
Get tutor help
How many solutions does the system have?
\newline
{
y
=
−
5
x
+
1
y
=
1
−
5
x
\begin{cases} y=-5x+1 \ y=1-5x \end{cases}
{
y
=
−
5
x
+
1
y
=
1
−
5
x
\newline
Choose
1
1
1
answer:
\newline
(A) Exactly one solution
\newline
(B) No solutions
\newline
(C) Infinitely many solutions
Get tutor help
Solve for
p
p
p
.
\newline
\begin{align*} 9(p-4)&=-18,\ p&=\Box \end{align*}
Get tutor help
Solve the equation.
\newline
11
=
7
v
v
=
□
\begin{array}{l} 11=7v \ v=\square \end{array}
11
=
7
v
v
=
□
Get tutor help
Solve the equation.
\newline
\begin{align*} \frac{w}{5} &= 3,\ w &= \Box \end{align*}
Get tutor help
Solve the equation. \begin{align*} 2 &= \frac{n}{3}, \ n &= \square \end{align*}
Get tutor help
Solve for
k
k
k
.
k
6
=
4
3
k
=
□
\begin{array}{l}\frac{k}{6}=\frac{4}{3} \\k=\square\end{array}
6
k
=
3
4
k
=
□
Get tutor help
Solve for
k
k
k
.
(
3
k
)
=
(
4
5
)
k
=
□
\begin{align*} \left(\frac{3}{k}\right)&=\left(\frac{4}{5}\right) \\ k&=\square \end{align*}
(
k
3
)
k
=
(
5
4
)
=
□
Get tutor help
Solve the equation.
\newline
2
3
p
=
5
p
=
□
\begin{align*} \frac{2}{3}p &= 5\\ p &= \Box \end{align*}
3
2
p
p
=
5
=
□
Get tutor help
Graph the solution of the following system of inequalities. Find the vertex of the solution.
\newline
{
x
+
y
≤
7
3
x
−
y
≥
9
\begin{cases} x+y \leq 7 \ 3x-y \geq 9 \end{cases}
{
x
+
y
≤
7
3
x
−
y
≥
9
Get tutor help
Graph the solution of the following system. Find the vertices of the solution.
\newline
{
y
≤
x
x
+
y
≥
3
x
≤
7
\begin{cases} y \leq x \ x+y \geq 3 \ x \leq 7 \end{cases}
{
y
≤
x
x
+
y
≥
3
x
≤
7
Get tutor help
The number of people using an older version of a spreadsheet program decreases at a rate that is proportional at any time to the number of people still using the version at that time.
\newline
There were
10
10
10
,
000
000
000
people using the older version of the spreadsheet program when the new version first came out. The number of people still using the older version decreases by
20
%
20 \%
20%
every
6
6
6
months.
\newline
How many people are still using the older version of the spreadsheet program after
2
2
2
months?
\newline
Choose
1
1
1
answer:
\newline
(A)
5848
5848
5848
\newline
(B)
9283
9283
9283
\newline
(C)
10
10
10
,
627
627
627
Get tutor help
Previous
1
...
4
5
