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Math Problems
Grade 7
Solve two-step equations with parentheses
Solve.
\newline
3
(
z
+
6
)
=
33
3(z+6)=33
3
(
z
+
6
)
=
33
\newline
Answer:
z
=
z=
z
=
Get tutor help
Solve.
\newline
7
(
z
+
3
)
=
28
7(z+3)=28
7
(
z
+
3
)
=
28
\newline
Answer:
z
=
z=
z
=
Get tutor help
Solve.
\newline
3
(
3
x
−
4
)
=
42
3(3 x-4)=42
3
(
3
x
−
4
)
=
42
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve.
\newline
7
(
z
−
2
)
=
28
7(z-2)=28
7
(
z
−
2
)
=
28
\newline
Answer:
z
=
z=
z
=
\newline
Submit Answer
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Solve.
\newline
3
(
2
y
+
3
)
=
39
3(2 y+3)=39
3
(
2
y
+
3
)
=
39
\newline
Answer:
y
=
y=
y
=
Get tutor help
Solve.
\newline
2
(
3
x
+
2
)
=
22
2(3 x+2)=22
2
(
3
x
+
2
)
=
22
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve.
\newline
3
(
3
z
+
5
)
=
33
3(3 z+5)=33
3
(
3
z
+
5
)
=
33
\newline
Answer:
z
=
z=
z
=
\newline
Submit Answer
Get tutor help
Solve.
\newline
2
(
5
y
+
7
)
=
44
2(5 y+7)=44
2
(
5
y
+
7
)
=
44
\newline
Answer:
y
=
y=
y
=
Get tutor help
Solve.
\newline
7
(
y
−
6
)
=
14
7(y-6)=14
7
(
y
−
6
)
=
14
\newline
Answer:
y
=
y=
y
=
Get tutor help
Solve.
\newline
7
(
z
+
2
)
=
49
7(z+2)=49
7
(
z
+
2
)
=
49
\newline
Answer:
z
=
z=
z
=
Get tutor help
Solve.
\newline
2
(
4
y
−
1
)
=
22
2(4 y-1)=22
2
(
4
y
−
1
)
=
22
\newline
Answer:
y
=
y=
y
=
Get tutor help
Solve.
\newline
7
(
z
−
2
)
=
28
7(z-2)=28
7
(
z
−
2
)
=
28
\newline
Answer:
z
=
z=
z
=
Get tutor help
Solve for
x
\mathrm{x}
x
.
\newline
2
(
−
2
x
+
1
)
−
2
x
+
1
=
−
27
2(-2 x+1)-2 x+1=-27
2
(
−
2
x
+
1
)
−
2
x
+
1
=
−
27
\newline
Answer:
Get tutor help
Solve for
x
\mathrm{x}
x
.
\newline
−
2
(
−
5
x
−
4
)
−
5
x
+
3
=
36
-2(-5 x-4)-5 x+3=36
−
2
(
−
5
x
−
4
)
−
5
x
+
3
=
36
\newline
Answer:
Get tutor help
Solve for
x
\mathrm{x}
x
.
\newline
−
4
(
−
2
x
−
4
)
+
2
x
+
5
=
31
-4(-2 x-4)+2 x+5=31
−
4
(
−
2
x
−
4
)
+
2
x
+
5
=
31
\newline
Answer:
Get tutor help
Solve for
x
\mathrm{x}
x
.
\newline
2
(
x
−
1
)
+
x
+
5
=
−
27
2(x-1)+x+5=-27
2
(
x
−
1
)
+
x
+
5
=
−
27
\newline
Answer:
Get tutor help
Solve.
\newline
2
(
7
y
+
3
)
=
34
2(7 y+3)=34
2
(
7
y
+
3
)
=
34
\newline
Answer:
y
=
y=
y
=
Get tutor help
Solve.
\newline
3
(
3
y
−
2
)
=
21
3(3 y-2)=21
3
(
3
y
−
2
)
=
21
\newline
Answer:
y
=
y=
y
=
Get tutor help
Solve.
\newline
3
(
3
z
+
5
)
=
33
3(3 z+5)=33
3
(
3
z
+
5
)
=
33
\newline
Answer:
z
=
z=
z
=
Get tutor help
Solve for
u
\mathrm{u}
u
.
\newline
10
=
u
8
10=\frac{u}{8}
10
=
8
u
\newline
Answer:
u
=
u=
u
=
Get tutor help
Solve for
x
x
x
.
\newline
48
=
12
+
9
10
x
48=12+\frac{9}{10} x
48
=
12
+
10
9
x
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve for
y
y
y
.
\newline
23
=
7
9
y
−
12
23=\frac{7}{9} y-12
23
=
9
7
y
−
12
\newline
Answer:
y
=
y=
y
=
Get tutor help
Solve for
z
z
z
.
\newline
3
4
z
+
8
=
68
\frac{3}{4} z+8=68
4
3
z
+
8
=
68
\newline
Answer:
z
=
z=
z
=
Get tutor help
Solve for
c
c
c
.
\newline
6
+
1
2
c
=
32
6+\frac{1}{2} c=32
6
+
2
1
c
=
32
\newline
Answer:
c
=
c=
c
=
Get tutor help
Solve for
z
z
z
.
\newline
2
3
z
+
5
=
55
\frac{2}{3} z+5=55
3
2
z
+
5
=
55
\newline
Answer:
z
=
z=
z
=
Get tutor help
Solve for
b
b
b
.
\newline
3
8
b
+
9
=
36
\frac{3}{8} b+9=36
8
3
b
+
9
=
36
\newline
Answer:
b
=
b=
b
=
Get tutor help
Solve for
b
.
b.
b
.
\newline
9
=
3
(
b
−
17
)
9 = 3(b - 17)
9
=
3
(
b
−
17
)
\newline
b
=
□
b=\square
b
=
□
Get tutor help
Solve for
b
.
b.
b
.
\newline
9
=
3
(
b
−
17
)
9 = 3(b - 17)
9
=
3
(
b
−
17
)
\newline
b
=
□
b=\square
b
=
□
Get tutor help
Solve for
d
.
d.
d
.
\newline
4
(
d
+
2
)
=
12
4(d + 2) = 12
4
(
d
+
2
)
=
12
\newline
d
=
□
d=\square
d
=
□
Get tutor help
Solve for
d
.
d.
d
.
\newline
4
(
d
+
2
)
=
12
4(d + 2) = 12
4
(
d
+
2
)
=
12
\newline
d
=
□
d=\square
d
=
□
Get tutor help
Solve for
d
.
d.
d
.
\newline
2
(
d
+
2
)
=
18
2(d + 2) = 18
2
(
d
+
2
)
=
18
\newline
d
=
□
d=\square
d
=
□
Get tutor help
Solve for
d
.
d.
d
.
\newline
2
(
d
+
2
)
=
18
2(d + 2) = 18
2
(
d
+
2
)
=
18
\newline
d
=
□
d=\square
d
=
□
Get tutor help
k
4
+
3
=
14
\frac{k}{4} + 3 = 14
4
k
+
3
=
14
Get tutor help
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