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Math Problems
Grade 6
Add integers
Evalute:
2
×
1
−
1
2 \times 1 - 1
2
×
1
−
1
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Add:
\newline
−
2
+
2
=
-2 + 2 =
−
2
+
2
=
_____
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Add:
\newline
−
1
+
2
=
-1 + 2 =
−
1
+
2
=
_____
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Add:
\newline
−
5
+
2
=
-5 + 2 =
−
5
+
2
=
_____
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Add:
\newline
−
1
+
5
=
-1 + 5 =
−
1
+
5
=
_____
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Solve.
\newline
1
−
1
5
=
1-\frac{1}{5}=
1
−
5
1
=
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Simplify.
\newline
(
−
12
)
−
5
=
_
_
_
_
_
(-12) - 5 = \_\_\_\_\_
(
−
12
)
−
5
=
_____
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Find the value of
(
−
6
)
+
(
−
3
)
−
4
(-6) + (-3) - 4
(
−
6
)
+
(
−
3
)
−
4
.
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7
−
1
=
7-1=
7
−
1
=
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Compute:
\newline
−
4
+
(
−
3
)
-4+(-3)
−
4
+
(
−
3
)
\newline
Answer:
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Compute:
\newline
11
−
(
−
2
)
11-(-2)
11
−
(
−
2
)
\newline
Answer:
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Compute:
\newline
5
−
(
−
3
)
5-(-3)
5
−
(
−
3
)
\newline
Answer:
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Compute:
\newline
(
−
11
)
−
(
−
5
)
(-11)-(-5)
(
−
11
)
−
(
−
5
)
\newline
Answer:
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2
+
2
=
2+2=
2
+
2
=
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