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Math Problems
Calculus
Find indefinite integrals using the power rule (Level 2)
Which of the following is equivalent to
log
c
(
6
)
log
(
6
)
\frac{\log_{c}(6)}{\log(6)}
l
o
g
(
6
)
l
o
g
c
(
6
)
?
\newline
Choose
1
1
1
answer:
\newline
(A)
log
(
c
)
\log(c)
lo
g
(
c
)
\newline
(B)
log
c
(
1
)
\log_{c}(1)
lo
g
c
(
1
)
\newline
(C)
1
log
(
c
)
\frac{1}{\log(c)}
l
o
g
(
c
)
1
\newline
(D)
1
log
(
6
)
\frac{1}{\log(6)}
l
o
g
(
6
)
1
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