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Math Problems
Algebra 2
Find the focus or directrix of a parabola
Look at the system of inequalities.
\newline
y
≤
−
1
2
x
+
4
y \leq -\frac{1}{2}x + 4
y
≤
−
2
1
x
+
4
\newline
x
≥
0
x \geq 0
x
≥
0
\newline
y
≥
0
y \geq 0
y
≥
0
\newline
The solution set is the triangular region where all the inequalities are true.
\newline
What are the vertices of that triangular region?
\newline
(____,____)
\newline
(____,____)
\newline
(____,____)
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Look at the system of inequalities.
\newline
y
≤
−
1
5
x
+
2
y \leq -\frac{1}{5}x + 2
y
≤
−
5
1
x
+
2
\newline
x
≥
0
x \geq 0
x
≥
0
\newline
y
≥
0
y \geq 0
y
≥
0
\newline
The solution set is the triangular region where all the inequalities are true.
\newline
What are the vertices of that triangular region?
\newline
(____,____)
\newline
(____,____)
\newline
(____,____)
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Simplify. Write your answer using whole numbers and variables.
\newline
m
−
9
m
2
−
9
m
\frac{m - 9}{m^2 - 9m}
m
2
−
9
m
m
−
9
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The system of inequalities
y
≥
−
x
−
3
y \geq-x-3
y
≥
−
x
−
3
and
y
≥
3
x
y \geq 3 x
y
≥
3
x
is graphed in the
x
y
x y
x
y
-plane. Which of the following is a solution to the system?
\newline
Choose
1
1
1
answer:
\newline
(A)
(
−
4
,
−
2
)
(-4,-2)
(
−
4
,
−
2
)
\newline
B)
(
−
2
,
0
)
(-2,0)
(
−
2
,
0
)
\newline
(C)
(
0
,
−
3
)
(0,-3)
(
0
,
−
3
)
\newline
(D)
(
3
,
4
)
(3,4)
(
3
,
4
)
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What is the focus of the parabola
y
=
−
x
2
y = -x^2
y
=
−
x
2
?
\newline
Simplify any fractions.
\newline
(_____ , _____)
\newline
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