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Math Problems
Algebra 1
Solve advanced linear inequalities
Solve for
x
x
x
.
\newline
Your answer must be simplified.
\newline
−
30
<
x
−
4
-30<\frac{x}{-4}
−
30
<
−
4
x
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Solve for
x
x
x
.
\newline
Your answer must be simplified.
\newline
7
>
x
4
7>\frac{x}{4}
7
>
4
x
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Solve for
z
z
z
.
\newline
12
=
15
(
z
−
1
5
)
12=15\left(z-\frac{1}{5}\right)
12
=
15
(
z
−
5
1
)
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Solve for
t
t
t
.
\newline
4
(
t
+
1
4
)
=
3
4\left(t+\frac{1}{4}\right)=3
4
(
t
+
4
1
)
=
3
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Solve for
k
k
k
.
\newline
k
2
+
1
2
=
3
\frac{k}{2}+\frac{1}{2}=3
2
k
+
2
1
=
3
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Solve for
y
y
y
.
\newline
y
−
1
3
y
+
7
=
1
10
y
=
□
\begin{array}{l} \frac{y-1}{3 y+7}=\frac{1}{10} \\ y=\square \end{array}
3
y
+
7
y
−
1
=
10
1
y
=
□
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Evaluate.
\newline
2
3
−
128
3
=
\frac{\sqrt[3]{2}}{\sqrt[3]{-128}}=
3
−
128
3
2
=
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Evaluate.
\newline
2
4
162
4
=
\frac{\sqrt[4]{2}}{\sqrt[4]{162}}=
4
162
4
2
=
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Evaluate.
\newline
−
16
5
⋅
2
1
5
=
\sqrt[5]{-16} \cdot 2^{\frac{1}{5}}=
5
−
16
⋅
2
5
1
=
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What is the slope of the line?
\newline
y
+
2
=
−
2
(
x
−
3
)
y+2=-2(x-3)
y
+
2
=
−
2
(
x
−
3
)
\newline
Choose
1
1
1
answer:
\newline
(A)
−
1
-1
−
1
\newline
(B)
−
2
-2
−
2
\newline
(C)
1
1
1
\newline
(D)
−
1
2
-\frac{1}{2}
−
2
1
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